Math, asked by ratandey1810, 1 month ago

The present age of a son is half the present age of his father. Ten years ago, the father was thrice as old as his son. What are their present age?​

Answers

Answered by Anonymous
6

Answer:

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

ATQ,

10 years ago, father's age was thrice as old as his son.

➡3(x - 10) = 2x - 10

➡3x - 30 = 2x - 10

➡3x-2x = -10 + 30

➡x = 20

Hence their present ages are :

Father's present age = 2x = 40 years

His son's present age=x=20 Years

Answered by harshitagsk
1

Answer:

Given that,

The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

 10 years ago, father's age was thrice as old as his son.

➡ 3(x - 10) = 2x - 10

➡ 3x - 30 = 2x - 10

➡ 3x - 2x = -10 + 30

➡ x = 20

Hence their present ages are:-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

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