The present age of a son is half the present age of his father. Ten years ago, the father was thrice as old as his son. What are their present age?
Answers
Answered by
6
Answer:
Let the present age of the father be 2x.
Therefore present age of the son = 2x/2 = x years
ATQ,
10 years ago, father's age was thrice as old as his son.
➡3(x - 10) = 2x - 10
➡3x - 30 = 2x - 10
➡3x-2x = -10 + 30
➡x = 20
Hence their present ages are :
Father's present age = 2x = 40 years
His son's present age=x=20 Years
Answered by
1
Answer:
Given that,
The present age of son is half the present age of his father.
Let the present age of the father be 2x.
Therefore present age of the son = 2x/2 = x years
10 years ago, father's age was thrice as old as his son.
➡ 3(x - 10) = 2x - 10
➡ 3x - 30 = 2x - 10
➡ 3x - 2x = -10 + 30
➡ x = 20
Hence their present ages are:-
Father's present age = 2x = 40 years
His son's present age = x = 20 years
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