Question

The present age of a son is half the present age of his father. ten year ago the father was thrice as old as his son. what are their percent age

Answer 1

Answer:

7:3

Step-by-step explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+10)+10=2[(x+10)+10]

⇒3x+20=2x+40

⇒x=20

∴ Required ratio =(3x+10):(x+10)=70:30=7:3

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Answer 2

The father present age is 40 years

The present age of his son is 20 years

Explanation:

Given:

1. The present age of a son is half the present age of his father

2. ten years ago the father was thrice as old as his son

To find:

The present age of father and son

Solution:

==> Let son age be, x

==> Let father age be, y

==> The present age of a son is half the present age of his father

==> $x =\frac{1}{2}y$  ==> 1

==> Ten years ago, son age be x-10

==> Ten years ago, Father age be y-10

==> According to this condition

==>3( x-10) = (y-10)

==> 3x-30 = y-10

==> 3x-y-30+10=0

==> 3x-y = 20 ==> 2

Substitute equation 1 in 2

==> $\frac{3}{2}y-y=20$

==> $\frac{3}{2}y-\frac{2}{2}y=20$

==>  $\frac{1}{2}y=20$

==>  $\frac{1}{2}y=20$

==>  y = 40

The father present age is 40 years

==> Substitute y value in equation 1

==>  $x =\frac{1}{2}y$  

==>  $x =\frac{1}{2}40$  

==> x = 20 years

The son's present age is 20 years