The present age of Anne ‘s mother is three times the present age of Anne .After 5 years sum of their age will be 66 years .Find their present age
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Let Anne's age be x and her mother's be 3x.
Now, after 5 years
(x+5) + (3x+5) = 66
4x + 10 = 66
4x = 56
x = 56/4
x = 14
Therefore Anne's age is 14 years and her mother's age is 42 years.
Now, after 5 years
(x+5) + (3x+5) = 66
4x + 10 = 66
4x = 56
x = 56/4
x = 14
Therefore Anne's age is 14 years and her mother's age is 42 years.
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The present age of Sahil’s mother is three times the present age of Sahil. After 5 years their ages will add to 66 years. Find their present ages.
Assume present age of sahil be x
Present age of his mother will be 3x
after 5 years
sahil age=x+5
his mothers age =3x+5.
According to question
(x+5)+(3x+5)=66
4x+10=66
4x=56
x=14
sahil present age=14 years
his mother present age= 42 years.
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