Math, asked by devanshu2837, 1 month ago

The present age of Aradhana and Aadrika is in the ratio 3:4. 5 years back, the ratio of their ages was 2:3. What is the present age of Aradhana?
12 years
15 years
20 years
22 years
10 years

Answers

Answered by devanshu1234321
60

QUESTION:-

The present age of Aradhana and Aadrika is in the ratio 3:4. 5 years back, the ratio of their ages was 2:3. What is the present age of Aradhana?

12 years

15 years

20 years

22 years

10 years

EXPLANATION:-

Let the present age of Aradhana be "3x"

and that of Aadrika be "5x"

5 years back their ages:-

Aradhana=3x-5

Aadrika=5x-5

ATQ,

\bf\;\frac{3x-5}{4x-5}=\frac{2}{3}\\\\3(3x-5)=2(4x-5)\\\\9x-15=8x-10\\9x-8x=-10+15\\x=5\;years

So the value of x is 5.

Which means:-

Aradhana=3(5)

=>15 yeas

Aadrike=4(5)

=>20 yea s

So Aradhana age=15 years

SO opt-[C] is correct answer

Answered by ankitpradhan665
0

Step-by-step explanation:

let present age of Aradhana and aadrika =. 3x and 4x

let age of Aradhana and aadrika 5 year back =

3x-5 = 2

4x-5 = 3

The present age Aradhana and aadrika=

 \frac{3x - 5}{4x - 5}  =  \frac{2}{3}

3(3x - 5) = 2(4x - 5)

9x - 15 = 8x - 10

9x - 8x =  - 10 + 15

x = 5

Aradhana age = 3× 5

= 15 years

Aadrika age = 4× 5

= 20 years

Please mark it as brainliest

Similar questions