Math, asked by mdirfanobra, 4 months ago

The present age of Aradhand and Asdrika is in tge ratio 3:4 5 years ago the r
atio of their ages was 2:3 What is the present ages of aradhand

Answers

Answered by bhattacharyyaakash22
0

Answer:

GIVEN :-

Ratio of Ages of Aradhana and Aradika = 3 : 4

Ratio of their ages 5 years ago = 2 : 3

TO FIND :-

The Present age of aradhana

SOLUTION :-

Let the Ratio constant be a. Then present age of aradhana becomes 3a and Age of aradhika becomes 4a.

5 years ago , Ages of aradhana and aradika becomes " 3a - 5 " and " 4a - 5 "

Then Ratio of their ages 5 years ago becomes (3a-5) : (4a-5)

But we are given that ratio of their ages 5 years ago as 2 : 3.

Then ,

Pressnt age of Aradhana = 3a = 3(5) = 15 years

Present age of Aradhika = 4a = 4(5) = 20 years

Step-by-step explanation:

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Answered by dhartinp2016
0

Answer:

Let the Ratio constant be a. Then present age of aradhana becomes 3a and Age of aradhika becomes 4a.

5 years ago , Ages of aradhana and aradika becomes " 3a - 5 " and " 4a - 5 "

Then Ratio of their ages 5 years ago becomes (3a-5) : (4a-5)

But we are given that ratio of their ages 5 years ago as 2 : 3.

\begin{gathered} \\ : \implies \sf \: \frac{3a - 5}{4a - 5} = \frac{2}{3} \\ \\ \end{gathered}

:⟹

4a−5

3a−5

=

3

2

\begin{gathered} \\ : \implies \sf \: 3(3a - 5) = 2(4a - 5) \\ \\ \end{gathered}

:⟹3(3a−5)=2(4a−5)

\begin{gathered} \\ : \implies \sf \: 9a - 15 = 8a - 10 \\ \\ \end{gathered}

:⟹9a−15=8a−10

\begin{gathered} \\ : \implies\underline{\boxed{\mathfrak {\pink{ a = 5}}}}\end{gathered}

:⟹

a=5

Then ,

Pressnt age of Aradhana = 3a = 3(5) = 15 years

Present age of Aradhika = 4a = 4(5) = 20 years

\begin{gathered} \\ \bigstar\: \underline{\sf{Hence\:, the\:present\:age\:of\:aradhana\:= \bold{15\:years}}} \\ \end{gathered}

Hence,thepresentageofaradhana=15years

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