Question

The present age of Ashok is equal to the square of his sons present age.One year ago, Mr Ashok was eight times as old as his son. Find Thier present age. PLZ answer std 10.from lesson quadratic equation.

Answer 1

Answer:

Sons age is 7 and Ashok age is $7^{2}$ = 49

Step-by-step explanation:

Let the age of Ashok = a

Let the age of his son = b

Its given that

a = $b^{2}$

One year ago

(a-1) = 8(b-1)

($b^{2}$ - 1) = 8(b-1)

($b^{2}$ - 1) = 8b - 8

$b^{2}$ - 8b - 7 = 0

$b^{2}$ - 7b - b - 7 = 0

b(b-7) - 1(b-7) = 0

(b-1)(b-7) = 0

b = 1 or b = 7

Here we will consider b = 7

So sons age is 7 and Ashok age is $7^{2}$ = 49