The present age of B will be half of A's age 4 years hence and double of A's age 5 years ago, then what is the present age of B?
(a) 6 years
(b) 4 years
(c) 8 years
(d) 12 years
Answers
Answer:
B's age = 10 years.
I'm sorry I can't write explanation for this but the answer is correct and the option is not correct
Given: Present age of B will be half of A's age after 4 year and double of A's age 5 years ago
To find: Present age of B
Let: B's present age = X years
A's present age = Y years
Solution: According to the given problem,
Present age of B will be half of A's age after 4 years.
A's age after 4 years will be (Y + 4) years
⇒ X = x (Y + 4) or X = Y/2 + 4/2 ...(1)
also, B's present age is double of A's age 5 years ago.
Age of A 5 years ago = (Y - 5)
⇒ X = 2 x (Y - 5) or X = 2Y - 10 ...(2)
Comparing both the values of X from equation (1) and (2)
⇒ Y/2 + 4/2 = 2Y - 10
⇒ 2Y - Y/2 = 4/2 + 10
⇒ =
⇒ 3Y/2 = 24/2 = 12
⇒ 3Y = 12 x 2 = 24
⇒ Y = 24/3 = 8
Putting value of Y in equation (2)
X = 2 x (8 - 5)
X = 2 x 3 = 6
Therefore, present age of B (X) is 6 years.