Question

the present age of bhuvan is 5 years and his father's age is 28 years. In how many years will the father's age be twice the age of his son?

Answer 1

Answer:

18 years

Step-by-step explanation:

Let after 'x' years father's age be twice the age of his son.

28 + x = 2(5 + x)

28 + x = 10 + 2x

28 - 10 = 2x - x

18 = x

i.e. x = 18

Therefore, after 18 years the father's age be twice the age of his son.

Answer 2

After 18 years father's age will be twice the age of his son

Given:

The present age of bhuvan is 5 years and

His father's age is 28 years

To find:

In how many years will the father's age be twice the age of his son

Solution:

Given Bhuvan's age = 5 years

His father's age = 28 years

Let after x years father's age will be twice the age of his son

After x years their ages  

Father's age = (28 +x) years

Bhuvan's age = (5+x) years

Given that after x years father's age will be twice the age of his son

⇒ (28 +x) = 2(5+x)

⇒ 28 + x = 10 + 2x

⇒ 2x - x = 28 -10

⇒ x = 18

Therefore,

After 18 years father's age will be twice the age of his son

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