The present age of brother and sister is in the ratio 4:5. Before three years the ratio of
their age was 3: 4. Find their present age.
Answers
- Present age of brother = 12 years
- Present age of sister = 15 years
Let the present age of brother and sister be 4x and 5x years respectively.
Before three years :-
- Brother's age = 4x - 3
- Sister's age = 5x - 3
In the question, it is stated that before three years the ratio of their age was 3: 4. So, according to the question :
- By using cross multiplication method.
- By distributive property,
- Performing multiplication.
- Transposing like terms.
- Performing addition & subtraction.
Henceforth,
→ Present age of brother = 4x years
→ Brother's age = 4(3) years
And,
→ Present age of sister = 5x years
→ Sister's age = 5(3) years
⠀⠀⠀⠀⠀_____________
In the question, it is stated that the present ages of them are in ration 4:5 and before three years the ratio of their age was 3:4. So,
LHS:
Reducing it to lowest terms.
RHS:
Therefore, LHS = RHS.
Hence, verified!!
Given :
- The present age of brother and sister is in the ratio 4:5.
- Before three years the ratio of their age was 3: 4.
To Find :
- Their Present Ages
Solution :
⟶ Let the Present Age of Brother be 4x
⟶ Let the Present Age of Sister be 5x
Before 3 Years :
⟶ The Present Age of Brother = 4x - 3
⟶ The Present Age of Brother = 5x - 3
⠀
According to the Question :
➟ 4x - 3 / 5x - 3 = 3/4
➟ 4 (4x - 3) = 3 (5x - 3)
➟ 16x - 12 = 15x - 9
➟ 16x - 15x = 12 - 9
➟ x = 3
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Therefore :
- Present age of Brother = 4x
- Present age of Brother = 4 × 3
- Present age of Brother = 12 years
- Present age of Sister = 5x
- Present age of Sister = 5 × 3
- Present age of Sister = 15years
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