Question

the present age of daughter and father are in the ratio 1:6. After 5 years the ratio of their ages will be 2: 7, what is the present age of the son who is 2 years younger than the daughter​

Answer 1

Answer:

3 years

Step-by-step explanation:

Let us assume:-

The present ages of :-

• Daughter = x
• Father = y
• Son = z

Present ages of daughter and father,

=> x : y = 1 : 6

=> x / y = 1 / 6

=> 6x = y

After 5 years,

=> (x + 5) : (y + 5) = 2 : 7

Substituting the value of y.

=> (x + 5) : (6x + 5) = 2 : 7

=> (x + 5) / (6x + 5) = 2 / 7

=> 7(x + 5) = 2(6x + 5)

=> 7x + 35 = 12x + 10

=> 35 - 10 = 12x - 7x

=> 25 = 5x

=> 25/5 = x = 5

The present age of the son,

=> z = x - 2

Putting the value of x.

=> z = 5 - 2

=> z = 3

Hence,

The present age of the son is 3 years.