Math, asked by Gitanjali3008, 9 months ago

THE PRESENT AGE OF DAVIDS MOTHER IS 1 MORE THAN FOUR TIMES HIS PRESENT AGE. AFTER 15 YEARS, THE RATIO OF DAVIDS AGE TO THIS MOTHERS AGE 1:2. FIND THE PRESENT AGE OF DAVID.

Answers

Answered by kalavathibathina1717
9

Step-by-step explanation:

let the present age of David be x

then,the present age of David's mother is (4 x + 1)

after 15 years

•David's age = x + 15

•David's mother age = 4x + 16

given that the ratio of David age to his mother age after 15 years is 1:2

\frac{x + 15}{4x + 16} = \frac {1}{2}

⇒2x + 30 = 4x + 16

⇒30 - 16 = 4x - 2x

⇒14 = 2x

⇒x = 7

Therefore the present age of David is 7

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