Question

The present age of father is 15 years more than twice the present age of the son. The present age of the mother of the son is twice the son's age. The sum of the present ages of the father and mother is 75 years. Find the sum of their ages when their son was born.

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Answer 1

Answer:15

Step-by-step explanation:

Let son's age be x

Father's age= 2x+15

Mother's age=2x

A.T.Q=> 2x+2x+15=75

=>x=15(present age of son)

Before how many years he was born it is not specified if so then just subtract it from 15 and you will get your answer

Answer 2

Answer:

$\huge\red{\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}}$

Let us take the present age of son be x.

Then, the age of father = 2x +15.

Then the present age of mother = 2x.

Then sum of present ages of mother and son =

Then sum of present ages of mother and son = 2x +2x +15 =4x+15

But, it is given 75yrs.

ATQ, 4x +15 =75.

→4x =75-15

→ 4x =60.

→ x =60/4.

Therefore x =15 yrs.

$\large\red{\boxed{Son's\: present\:age=x=15yrs}}$

So, present age of father =2x+15=2×15+15=45yrs.

$\large\red{\boxed{Father present age=45yrs.}}$

Therefore age of father 15 yrs. ago =45-15=30yrs

$\large\red{\boxed{mother's\: present \:age =2x=30yrs.}}$

Therefore age of mother 15yrs.ago=30-15=15yrs.

Therefore age of mother 15yrs.ago=30-15=15yrs.so, sum of ages = 15+30=45yrs.

$\large\green{\boxed{SUM\: OF\: AGES =45YRS}}.$