Question

the present age of father is 3 times of his son after 5 years the sum of their ages would be 70 years find their present ages​

Answer 1

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Given:

•The present age of the father is 3 times that of his son.

•5 years ago, the sum of their ages is 70 years.

To find:

• Their present age.

Explanation:

•Assume the present age of son be R years.

•The present age of father be 3R years.

Five years ago;

• The son's age = (R-5) years
• The father's age = (3R-5) years.

According to the question:

=) (R-5)+ (3R-5)=70

=) R-5 +3R-5=70

=) 4R-10=70

=) 4R= 70+10

=) 4R= 80

=) R= 80/4

=) R= 20 years

Therefore,

The present age of the son is 20 years.

The present age of the father is 3R years

=) 3×20 years

=) 60 years

Answer 2

Answer:

age of son=15 age of his father=45

Step-by-step explanation:

y=3x

x+y+10=70

4x=60

x=15