Math, asked by abhistrange, 1 year ago

the present age of father is 3 years more than three times the age of his son.3 years after father's age will be 10 years more than twice the age of the son. the father's present age is

Answers

Answered by sharishk2003
6

Hey dear, This is your answer,

Mark me brainliest if it's correct

Attachments:

abhistrange: thanks
sharishk2003: it's okay
shilasinghprasad31: This answer is wrong
sharishk2003: Could you please tell me why?
shilasinghprasad31: I have uploaded the correct answer in the answer section
shilasinghprasad31: you can see my answer and then correct your mistakes
Answered by shilasinghprasad31
2

Step-by-step explanation:

Let's take son's present age as X years

Then, Father's present age =3+3x years

After 3 years years

Son's age = X+3 years

Father's age= 3+3x+3=10+(2x+3+3)years

= 3x+6=10+6+2x years

= 3x-2x=10+6-6 years

= X= 10 years

Therefore, Father's present age = 3+3x years

= 3+(3×10) years

= 3+30 years

= 33 years

Answer= Son's present age=10 years

Father's present age=33 years

Similar questions