Math, asked by sunilsharma17, 1 year ago

the present age of father is 3 years more than three times the age of son 3 years hence father's age will be 10 year more than twice the age of the son determine their present age​

Answers

Answered by pratyush4211
25

Present Age of Father is 3 years more than 3 times the present age of Son.

Let Present Age of Son=x years

Then present age of Father=(3x+3) years

After 3 years

Age of Son will be=(x+3) years

Age of Father will be=(3x+3+3)=(3x+6) years

Age of Father after 3 years is 10 more than 2 times the age of his son After 3 years

Means

Age of Father after 3 years=2×Age of Son after 3 years +10

(3x+6)=2(x+3)+10

3x+6=2x+6+10

3x-2x=6+10-6

x=10

Age of Son=x=10 years

Age of Father=3x+3=3×10+3=33 years

Son=10 years

Father=33 years

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