Math, asked by john07robin, 6 months ago

the present age of father is 4 times age of his son. after 10 years, the age of father will become 3 times age of his son. find their present ages.

Answers

Answered by veerasharma2006
1

Answer:

ok

Step-by-step explanation:

Let the son's present age be x .

Father's present age = 4x

After 10 years,

Son's age = x+10

Father's age = 4x+10

4x+10=3(x+10)

4x+10=3x+30

4x-3x=30-10

x=20

Son's present age = 20

Father's present age =4x = 4×20=80

Answered by aradhygupta51
0

Answer:

father age =80

son's age=20

Step-by-step explanation:

let the son's age be x then father's age will be 4x:

4x+10=3(x+10

4x+10=3x+30

x=20

here is the son's age

so fathet will be :

4x=4×20

=80

hope u have understood

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