Math, asked by RAGHAVENDRA8353, 5 months ago

the present age of father is 4 times the age of his son after 10 years age of father will become three times the age of his son find their present ages​

Answers

Answered by MystícPhoeníx
186

Answer:

  • Present age of Father = 80 Years
  • Present age of his son = 20 Years.

Step-by-step explanation:

Solution:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Given Statement !!

The present age of father is 4 times the age of his son

Let the Present age of his son be x years

∴ The Present age of his father be 4x ------(i)

And,

After 10 years age of father will become three times the age of his son

→ 4x +10 = 3(x+ 10)

→ 4x + 10 = 3x + 30

→ 4x -3x = 30-10

→ x = 20

Putting x = 20 in equation (i) we get

→ 4x = 4×20 = 80 Years

  • Hence, the present age of father is 80 years & present age of his son is 20 years.
Answered by BrainlyHero420
185

Answer:

Given :-

  • The present age of father is 4 times the age of his son after 10 years of father will become three times the age of his son.

To Find :-

  • What is their present ages.

Solution :-

Let, the present age of son be x

And, the present age of his father will be 4x

After 10 years,

Age of son is x + 10

And, age of his father is 4x + 10

According to the question,

4x + 10 = 3(x + 10)

4x + 10 = 3x + 30

4x - 3x = 30 - 10

x = 20

Hence, their required present ages are,

Present age of son = x = 20 years

Present age of his father = 4x = 4(20) = 80 years

The present age of son is 20 years and the present age of his father is 80 years .

Let's Verify :-

4x + 10 = 3(x + 10)

Put x = 20 we get,

4(20) + 10 = 3(20 + 10)

80 + 10 = 60 + 30

90 = 90

LHS = RHS

Hence, Verified

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