The present age of father is 4 times the age of his son. After 10 years, age of father will become 3 times the age of his son, find their present ages
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Answered by
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ANSWER:
Let
the father's age be 4x
the son's age be x
So, after 10years
the father's age is 4x + 10
the son's age is x+10
4x + 10 = 3 * (x+ 10)
4x + 10= 3x + 30
4x -3x = 30 - 10
x = 20
therefore father's present age = 4x =4 * 20 = 80 years old
son's present age => 20 years old
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Answered by
0
Answer:
Step-by-step explanation:
Let
the father's age be 4x
the son's age be x
So, after 10years
the father's age is 4x + 10
the son's age is x+10
4x + 10 = 3 * (x+ 10)
4x + 10= 3x + 30
4x -3x = 30 - 10
x = 20
therefore father's present age = 4x =4 * 20 = 80 years old
son's present age => 20 years old
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