Math, asked by keshaverma805, 3 months ago

the present age of father is five times the age of his son. After 5 years, age of father will become three times the age of his son. find their present ages​

Answers

Answered by mathursaloni2287
0

Answer:

5 and 25

Step-by-step explanation:

present age of son = x =.5

present age of father = 5x = 25

after 5 years (+5)

3(x + 5) = 5x + 5

3x + 15 = 5x + 5

2x = 10

x = 5

Answered by Growww28
0

Answer:

Father present age =40 years

 Son present age =10 years

Step-by-step explanation:

years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30....eq2

Put  the value of x from eq1

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3× 10+10=40

 

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