Math, asked by jpjitendra5853, 10 months ago

The present age of father is four times that of his son, 5 years hence the age of father would be three times that of his son, find the present age of father and son in years

Answers

Answered by ramanathanharshini
0

Answer:

Step-by-step explanation:

Present age:

SON-x

FATHER-4x

After 5 years,

SON-x+5

FATHER-4x+5=3(x+5)=3x+15

4x+5=3x+15

x=10

son=10,then

Father=4x=40

Answered by Anonymous
4

Answer:

Let the present age of son be x years and present age of father will be 4x years.

According to Question now,

➳ 3(x + 5) = 4x + 5

➳ 3x + 15 = 4x + 5

➳ 15 - 5 = 4x - 3x

x = 10 years

Therefore,

  • Present age of son = x = 10 years

  • Present age of father = 4x = 40 years
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