The present age of father is four times the age of his daughter. After 10 years, the age of father will become three times the age of his daughter. Find their present age
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Answered by
1
let the present age of daughter be x
let the present age of father be 4x
after 10 years
father age = 4x+10
daughter age= x+10
A.T.Q
4x+10= 3(x+10)
4x+10=3x+30
4x-3x=30-20
x= 10
so the present age of daughter=x
x= 10
the present age of father = 4x
= 4×10
= 40
let the present age of father be 4x
after 10 years
father age = 4x+10
daughter age= x+10
A.T.Q
4x+10= 3(x+10)
4x+10=3x+30
4x-3x=30-20
x= 10
so the present age of daughter=x
x= 10
the present age of father = 4x
= 4×10
= 40
Answered by
2
Let the present age of the daughter be x
then father's present age = 4x
now after 10 yrs
4x + 10 = 3 (x+10)
4x + 10 = 3x + 30
4x -3x = 30-20
x = 10
so daughter's present age = 10 yrs
and father's present age = 4× 10 = 40 yrs
And ur information is wrong . after 10 yrs he will be 50 and the daughter 20 then it will not be 3 times. The question must be having 'after 5 years' or 15 yrs also.
then father's present age = 4x
now after 10 yrs
4x + 10 = 3 (x+10)
4x + 10 = 3x + 30
4x -3x = 30-20
x = 10
so daughter's present age = 10 yrs
and father's present age = 4× 10 = 40 yrs
And ur information is wrong . after 10 yrs he will be 50 and the daughter 20 then it will not be 3 times. The question must be having 'after 5 years' or 15 yrs also.
awesomeangelsfly:
Ok! My question said
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