The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their ages.
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Answer:
present age of father = 80 years
present age of his son = 20 years
Step-by-step explanation:
let the present age of father = x
and present age of his son = y
A.T.Q
x = 4y ------(1)
(x + 10) = 3(y + 10)
x + 10 = 3y + 30
x - 3y = 30 - 10
x - 3y = 20 -------(2)
put x = 4y in eq 2
4y - 3y = 20
y = 20
put y in eq 1
x = 4y
x = 4 × 20
x = 80
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