Math, asked by DebendraSwain, 10 months ago

The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their present ages.​

Answers

Answered by jyotishwarraval
1

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Answered by Avvid
2

Let the present age of son be X years.

the present age of father=4x yrs.

After 10 yrs,

Age of son=(x+10)yrs

Age of father=(4x+10)yrs

According to question,

4x+10=3(x+10)

4x+10=3x+30

4x-3x=30-10

x=20

Present age of son is 20 yrs

& present age of father= 4x=4×20=80 yrs.

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