Math, asked by adityanegi715, 10 months ago

the present age of father is four times the age of his son after 10 years age of father will become three times the age of his son find their present ages​

Answers

Answered by mohitsingh18
4

Answer:

father's age 80, son's age=20

Step-by-step explanation:

let the son age be x and father age 4x

after 10 years=4x+10

A/Q

(4x+10)=3(x+10)

(4x+10)=3x+30

4x-3x=30-10

x=20

Hence,the age of son is 20 years and the age of father is 20×4=80 years.

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