Math, asked by mk474659, 10 months ago

The present age of father is four times the age of his son. After 10 years, age

of father will become three times the age of his son. Find their present ages.

Answers

Answered by utkarshkumar2406
1

Step-by-step explanation:

present age of father = 4x

present age of son = x

After 10 years

age of son = (x+10)

age of father = (4x+10)

now

(4x+10) = 3(x+10)

4x+10 = 3x+30

4x-3x = 30-10

x = 20

present age of son = 20 yrs

present age of father = 20*4 = 80 yrs

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