Question

The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find the present age of father. *



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Answer 1

Answer:

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Step-by-step explanation:

consecutive terms is constant. Hence, it is known as constant difference (d).

That means, the difference between the first and second term = difference between the second and third term..

Or we can consider the opposite. The difference will remain constant throughout.

Hence:-

➛ 2nd - 1st = 3rd - 2nd

➛ 2x + p - x = 3x + 6 - (2x + p)

➛ x + p = 3x + 6 - 2x - p

➛ x + p = x - p + 6

➛ x + p - x + p - 6 = 0

➛ 2p - 6 = 0

➛ 2p = 6

➛ p = 3(Ans)

Answer 2

Answer:

Let the present age of son be x. Present age of father=4x. Now, Ten year hence his father age will be 3 times his son.

Step-by-step explanation:

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