Question

The present age of father is four times the age of his son . After 10 years age of father will become three times the age of his son . Find their present age

Answer 1

Answer:

Present age of father = 80 years

Present age of his son = 20 years.

Step-by-step explanation:

Let the present age of son be x year.

Therefore, the present age of father be 4x years.

According to the given condition

• After 10 years age of father will become three times the age of his son.

→ 4x+10 = 3(x+10)

→ 4x +10 = 3x + 30

→ 4x-3x = 30-10

→ x = 20

Putting the value of x = 20

→ 4x = 4×20 = 80

• Hence, the present age of father and his son are 80 & 20 years respectively .

Answer 2

Answer:

Given :-

• The present age of father is four times the age of his son. After 10 years age of father will become three times the age of his son.

To Find :-

• What is their present ages.

Solution :-

Let,

$\mapsto \sf\bold{Present\: age\: of\: son =\: y\: years}$

$\mapsto \sf\bold{Present\: age\: of\: father =\: 4y\: years}$

$\red{\bigstar}\: \: \bf{According\: to\: the\: question\: :-}$

$\implies \sf 4y + 10 =\: 3(y + 10)$

$\implies \sf 4y + 10 =\: 3y + 30$

$\implies \sf 4y - 3y =\: 30 - 10$

$\implies \sf y =\: 20$

$\implies \sf\bold{\purple{y =\: 20\: years}}$

Hence, the required present age of son and his father are :

$\clubsuit\: \: \sf\bold{\green{Present\: age\: of\: son\: :-}}$

$\longrightarrow \sf y\: years$

$\longrightarrow \sf\bold{\red{20\: years}}$

$\clubsuit\: \: \sf\bold{\green{Present\: age\: of\: father\: :-}}$

$\longrightarrow \sf 4y\: years$

$\longrightarrow \sf 4(20)\: years$

$\longrightarrow \sf 4 \times 20\: years$

$\longrightarrow \sf\bold{\red{80\: years}}$

$\therefore$ The present age of son and his father is 20 years and 80 years respectively.

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VERIFICATION :-

$\leadsto \tt{4y + 10 =\: 3(y + 10)}$

By putting y = 20 we get,

$\leadsto \tt{4(20) + 10 =\: 3(20 + 10)}$

$\leadsto \tt{80 + 10 =\: 3(30)}$

$\leadsto \tt{\bold{\pink{90 =\: 90}}}$

Hence, Verified.