Question

The present age of father is four times the age of his son. After 10years, age of father will become three times the age of his son. Find their present ages? *

Answer 1

⇝ Question :-

The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their present ages.

⇝ Answer :-

$\small\pink{\begin{cases} \bf Father's\:Present\:Age = 80 \:years \\  \\  \bf Son's\:Present\:Age = 20 \: years\end{cases}}$

⇝ Step by step Explanation :-

Let us Assume that,

• Son's Present Age = $\large \rm x$ years

❒ As The present age of father is four times the age of his son

Therefore,

• Father's Present Age = $\large \rm 4x$ years

❒ After 10 Years ;

• Age of Son = $\large \rm (x+10)$ years

• Age of Father = $\large \rm (4x+10)$ years

✧ According To Question,

$\blue \bigstar \: \red{ \pmb{\text{Father's Age = 3(Son's Age)}}}$

$:\longmapsto \rm 4x + 10 = 3(x + 10)$

$:\longmapsto \rm 4x + 10 = 3x + 30$

⏩ Seprating Both Type of terms ;

$:\longmapsto \rm 4x - 3x = 30 - 10$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf x = 20} }}}$

∴ Son's Present Age = 20 Years

As Given in the Question that The present age of father is four times the age of his son ;

$\therefore \text{Father's Present Age = 4(20)}$

∴ Father's Present Age = 80 Years

Answer 2

Answer:

$\sf\tt\large{\green {\underline {\underline{⚘\;Question:}}}}$

• The present age of father is four times the age of son.After 10 years, the age of father becomes three times the age of son.Find their present ages.

$\sf\tt\large{\red {\underline {\underline {⚘\;Answers:}}}}$

• The present age of son is 20 years.
• The present age of his father is 80 years.

$\sf\tt\large{\blue {\underline {\underline{⚘\;Given:}}}}$

• The present ages of father is four times the age of his son. After 10 years the age of his father becomes three times the age of his son.

$\sf\tt\large{\blue {\underline {\underline{⚘\;To find:}}}}$

• Finding their present ages.

$\sf\tt\large{\red {\underline {\underline {⚘\;Solution:}}}}$

$\sf\tt\large{\green {\underline {\underline{⚘\;Consider:}}}}$

• The present age of son be x years
• The present age of father =4x years.

$\sf\tt\large{\red {\underline {\underline{⚘\;Case (i):}}}}$

《After 10 years》

• The age of don becomes =(x+10)years.
• The age of father becomes =(4x+10)years.

$\sf\tt\large{\red {\underline {\underline{⚘\;From \;the\;question:}}}}$

• Father's age =3 (son's age)

Now,

• Applying the values we get that,

$4x + 10 = 3(x + 10)$

• By solving this we get that,

• 4x+10=3x+30
• 4x-3x=30-10
• x=20.

$\sf\tt\large{\green {\underline {\underline{⚘\;Therefore:}}}}$

• The present age of son =20years.

And,

• The present age of his father =4x=4×20=80years.

$\large{\bf{\green{\mathfrak{\dag{\underline{\underline{Which \; is \; the \;required \; Answer}}}}}}}$

Hope it helps u mate .

Thank you .