Question

The present age of father is four times the age of his son after ten years age of father will become three times the age of his son find their present ages

Answer 1

Answer:

son's present age= x=20

father's present age=80

Step-by-step explanation:

METHOD 1

Let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

son's present age = x=20

therefore father's present age = 4x

=4×20 = 80

father's present age=80

son's present age = x=20

METHOD 2

Let the son's present age be x .

Father's present age = 4x

After 10 years,

Son's age = x+10

Father's age = 4x+10

4x+10=3(x+10)

4x+10=3x+30

4x-3x=30-10

x=20

Son's present age = 20

Father's present age =4x = 4×20=80

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