Math, asked by janvisharma8142, 9 months ago

The present age of father is four times the age of son . after 10 years , age of father become 3 times the age of son . find there present age.

Answers

Answered by rikdas914
0

Answer:

present age of father is 80 yerars and and son is 20 years

Attachments:
Answered by BrainlyRaaz
3

Given :

  • The present age of father is four times the age of son.
  • After 10 years , age of father become 3 times the age of son.

To find :

  • Their present ages =?

Step-by-step explanation :

Let, the present age of son's be, x.

Then, the present age of Father's be, 4x.

After 10 years son's age = x + 10.

After 10 years Father’s age = 4x + 10.

According to the question,

3(x + 10) = 4x + 10

3x + 30 = 4x + 10

3x - 4x = 10 - 30

-1x = - 20

x = 20.

Therefore, We got the value of, x = 20.

Hence,

The present age of son's, x = 20 years.

Then, the present age of Father's , 4x = 4 × 20 = 80 years .

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