The present age of father is four times the age of son. After 10 years,the father will become three times the age of son. The age of father after 5 years will be
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Age of son =x
Age of father =4x
After 10 years,
Age of father=4x+10
Age of son=x+10
4x+10=3(x+10)
x=20
Father's age now=4x=80
After 5 years father's age =85
Age of father =4x
After 10 years,
Age of father=4x+10
Age of son=x+10
4x+10=3(x+10)
x=20
Father's age now=4x=80
After 5 years father's age =85
Answered by
1
Hi,
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Here is your answer,
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=======
=======:
Here is your answer,
=======:
:::YOUR ANSWER IS IN THE FORM OF PICTURE :::
=======
HOPE YOU WILL UNDERSTAND MY WORDS, a request is here please as I am an ACE ranker I wish that to make my way easy for the GENIUS rank you should mark my answer brainlest if you wish then only ☺.
=======
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Yadaiah:
you ca do it like this. Son age =y then Father=4y (after 10 years) father=4y+10 = 3(son's age ):- 4y+10=3y+30 :- 4y-3y=30-10:- { y= 20} why r u using long process
you ca do it like this. Son age =y then Father=4y (after 10 years) father=4y+10 = 3(son's age ):- 4y+10=3y+30 :- 4y-3y=30-10:- { y= 20} why r u using long process
you ca do it like this. Son age =y then Father=4y (after 10 years) father=4y+10 = 3(son's age ):- 4y+10=3y+30 :- 4y-3y=30-10:- { y= 20} why r u using long process
ok
Ok
be different from others
That's great tqs for responding fr my question
always for you all dear
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