The present age of father is fpur timmes that of son . 20 years hence, the age of father will be twice the age of the son at tht time . Find the present ages
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Father's age = 4x, son's age = x.
After 20 years, the father's age will become twice the son's age.
4x + 20 = 2(x+20).
4x + 20 = 2x + 40.
4x - 2x = 40 - 20.
2x = 20.
x = 10 years.
Hence, father's age 4x = 4 × 10 = 40 years.
Son's age = x = 10years.
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After 20 years, the father's age will become twice the son's age.
4x + 20 = 2(x+20).
4x + 20 = 2x + 40.
4x - 2x = 40 - 20.
2x = 20.
x = 10 years.
Hence, father's age 4x = 4 × 10 = 40 years.
Son's age = x = 10years.
Hope it helps you.
Mark me as the brainliest.
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