Math, asked by kaushik1920, 11 months ago

the present age of father is three years more than three times of his son three years hence father's agewill be 10 more than twice of his son find their present age​

Answers

Answered by anr4u97
0

This is ur answer

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Answered by aman240292
0

Let father’s age be x & son’s age be y

By 1st condition:

3 + 3y = x (three plus three times age of son is father’s age)

By 2nd condition:

x + 3 = 2(y + 3) + 10 [here we are talking about 3 years hence. So 3 has to be added to their present ages, and then satisfy the condition]

So the final 2 equations are

x-3y = 3 … (1)

x-2y = 13 … (2)

Solving them we get

y = 10, x = 33

So the father’s present age is 33 and that of the son is 10.

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