Question

The present age of father is twice of his son's 16years earlier father's age thrice that was of the son. Find the present ages.

Answer 1

Answer:

Present age of his son = 32 years

Present age of his father = 64 years

Step-by-step explanation:

given that,

The present age of father is twice of his son's age

let the age of his son be x

so,

age of his father will be 2x

also given that,

16 years earlier

father's age thrice that was of the son.

so,

According to the question,

2x - 16 = 3(x - 16)

2x - 16 = 3x - 48

3x - 2x = -16 + 48

x = 32

so,

age of his son = 32 years

age of his father = 2x

= 2(32)

= 64 years

so,

_________________

Present age of his son = 32 years

present age of his father = 64 years

_________________

Verification

16 years earlier

father's age thrice that was of the son.

=> 64 - 16 = 3(32 - 16)

= 48 = 3(16)

48 = 48

_________

Answer 2

Answer:-

Father age = 64 years

Son age = 32 years

Given :-

Present age of father is twice the age of his son.

16 years earlier father's age was thrice son age.

To find :-

Their present age.

Solution:-

Let the present age of father and son be x and y years respectively.

A/Q

$x = 2y -------1$

16 years earlier

Age of son was = (y -16)

Age of father = ( x - 16)

→$(x-16) = 3(y-16)$

→$x-16 = 3y -48$

→$x-3y = -48 +16$

→$x-3y = - 32 -----2$

Put the value of eq.1 in eq. 2

→$x = 2y$

→$2y-3y = -32$

→$-y = -32$

→$y = 32 years$

→ x = 2y

→x = 2 × 32

→x = 64 years.

hence ,

Son present age is 32 years.

Father present age is 64 years.