Question

The present age of father is twice that of the elder son.10 years later the age of the father will be three times of the youngest and the difference between the ages of two sons is15 the present age of father is
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Answer 1

Answer:

50 years

Step-by-step explanation:

let elder son be x

father = 2x

y = younger son=(x-15)  

10 years later

 

2x+10=3(x-15+10)

2x+10=3(x-5)

3x-2x=25  

x=25

y=10

father = 50