The present age of Geetha is 1/3 of the present age of her mother. After 5 years, sum of their ages will be 46. Form a linear equation in one variable to find the present ages of Geetha and her mother. What are Geetha's and her mother's ages?
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Answers
Answer:
Present Age of Geetha = 1/3 of the present age of her mother.
After 5 years the sum of their ages = 46
Let Geetha's Mother Age be x
So,
Geetha's Age = 1/3 x x
After 5 years their Age =
x + 5 + 1/3x + 5 = 46
x + 1/3x = 46 - 10
x + 1/3x = 36
(x + 1/3x = x + x/3
Now making common denominator, =
x/ 1 = 3x/3
So,
3x/3 + x/3 = 3x + x/3
= 4x/3 = 36
Now multiplying both sides to cancel denominator
So,
4x/3 x 3 = 36 x 3
4x = 108
x = 108/4
x= 27
So ,
Geetha's mother's present age will be 27
Geetha's age will be 27/3 = 9
Answer:
Complete step-by-step answer:
Let the present age of Prabha be x.
According to the question, the present age of Prabha’s mother is three times the present age of Prabha.
So, let the present age of Prabha’s mother be 3x .
After 5 years Prabha’s age will be x+5
And after 5 years Prabha’s mother’s age will be 3x+5
According to the question, after 5 years their ages will add to 66 years.
Hence, (x+5)+(3x+5)=66
Expanding the above equation we get,
x+5+3x+5=66
Adding the similar terms of the left hand side of the above equation we get,
4x+10=66
Subtracting 10 from the both of the side,
4x+10−10=66−10
⇒4x=56
Dividing 4 in both of the side,
4x4=564
∴ x=14
As we have taken x as the present age of Prabha earlier, so the present age of Prabha is 14 years.
∴ The present age of Prabha’s mother is, 3x=3×14=42 years
Therefore, the present ages of Prabha and Prabha’s mother are 14 years and 42 years respectively.
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Step-by-step explanation:
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