The present age of Geetha is 1/3 of the present age of her mother. After 5 years, sum of their ages will be 46. Form a linear equation in one variable to find the present ages of Geetha and her mother. What are Geetha's and her mother's ages?
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Given :-
The present age of Geetha is 1/3 of the present age of her mother. After 5 years, sum of their ages will be 46
To Find :-
What are Geetha's and her mother's ages
Solution :-
Let the age of her mother be m
Age of Geetha = m/3
After 5 years
Age of mother = m + 5
Age of Geetha = m/3 + 5
m/3 + 5 + m + 5 = 46
m/3 + 5 + m + 5 = 46
m + 15 + 3m + 15/3 = 46
4m + 30/3 = 46
4m + 30 = 3(46)
4m + 30 = 138
4m = 138 - 30
4m = 108
m = 108/4
m = 27
Now
Age of Geetha = 1/3 × m
Age of Geetha = 1/3 × 27
Age of Geetha = 9 years
Step-by-step explanation:
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- Heat is generated continuously in an electric heater, but its temperature becomes constant after some time. ... This is because a stage reaches when rate at which heat is generated by electric current becomes equal to the rate at which heat Is lost by radiation. Thermal equilibrium is reached.
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