Math, asked by raghav172, 1 year ago

the present age of husband and wife are in the ratio 4ratio3.thirty years later,the husband will be 10 years older to her.what are there present aged

Answers

Answered by Riddhigupta1024
2
Let age of husband = x
Let age of wife = y
ATQ
x/y = 4/3
3x = 4y
3x - 4y = 0 equation 1
Thirty yrs later
Age of husband = x + 30
Age of wife = y + 30
Again ATQ
x + 30 = y + 30 + 10
x - y = 10
x = 10 + y equation 2
Now putting value of x in equation 1
3 ×(10+y) - 4y = 0
30 + 3y -4y = 0
-y = -30
y = 30
Now putting value of y = 30 in equation 2
x = 10 + 30
x = 40
Therefore age of husband is 40 and age of wife is 30... I hope it helps

raghav172: thanks
Riddhigupta1024: Anytime
Riddhigupta1024: Can u Mark it as brainliest?
raghav172: Yes
raghav172: and ok
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