Question

The present age of Jake is 4 times the present age of Abdul. After 10 years, twice
Jake's age will be 4 times Abdul's age. What are their present ages?​

Answer 1

Answer:

Abdul's age is 5 Jakes age is 20

Answer 2

$\underline{\pink{ At \: present :}}$

$Let \:Age \: of \: Abdul = x \: years$

$Age \: of \: Jake = 4x \: years$

$\underline{\pink{ After \: 10 \: years :}}$

$Age \: of \: Abdul = ( x + 10 ) \: years$

$Age \: of \: Jake = (4x+10) \: years$

/* According to the problem given */

$2\: times \:of \: Jake's \:age = 4 \: times \: Abdul's \:age$

$\implies 2(4x+10) = 4(x+10)$

$\implies 8x + 20 = 4x + 40$

$\implies 8x - 4x = 40 - 20$

$\implies 4x = 20$

$\implies x = \frac{20}{4}$

$\implies x = 5$

Therefore.,

$\red{Present \:age \:of \: Abdul } \green { = 5 \: years }$

$\red{Present \:age \:of \: Jake }$

$= 4x$

$= 4 \times 5$

$\green { = 20 \: years }$

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