Question

the present age of jeeva's mother is two times the present age of jeeva after 5 years their ages will add to 40 years find their present ages

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Answer 1

Answer:

If the present age of the mother of Jeeva is 2 times the age of Jeeva and after 5 years, the sum of their ages becomes 40, then his age and the age of his mother are 10 and 20 respectively.

Step-by-step explanation:

Let J and M be the present ages of Jeeva and mother

Given

The present age of his mother = 2* present age of Jeeva

That is, M = 2J

Also, after 5 years,

Jeeva's age + mother's age = 40

That is, (J+5)+(M+5)=40

J+M+10 = 40

J+M = 40-10

J+ M = 30

M= 2J

So, J+M = J+ 2J = 3J

That is, 3J= 30

J= 30/3 = 10 years

So Jeeva's present age is 10 years

The present age of his mother = 2J = 2*10 = 20 years

Answer 2

Answer:

If the present age of Jeeva's mother is two times the present age of Jeeva after 5 years their ages will add to 40 years, then mother's present age is 20 years, and Jeev's present age = 10 years.

Step-by-step explanation:

Let the age of mother and  Jeev's be x,y respectively

x=2y -------- (1)

after 5 years mothers age =x+5

after 5 years Jeev's  age =y+5  

As per given condition

sum of their age 40

 x+5+y+5  = 40

 x+y+10 = 40

x + y = 40 - 10

x + y  = 30 ------- (2)

put x=2y in (2)

2y+y = 30

3y = 30

y =10

put y=10 in (1)

x = 2y = 2(10) = 20

So mothers present age is 20 years

and Jeev's  present age = 10 years