The present age of John's father is 10 years more than twice the present age of John. After 10 years, age of John's father will be twice the John's age. Find their current ages.
Answers
Answered by
37
Given :
- The present age of John's father is 10 years more than twice the present age of John.
- After 10 years, age of John's father will be twice the John's age.
To find :
- Their current ages =?
Step-by-step explanation :
Let, the present age of John's be, x.
Then, the present age of John's father be, 2x + 10.
After 10 years John's age = x + 10
After 10 years John's father's age = 2x + 10 + 10
According to the question,
2x + 10 + 10 = 2(x + 10) + 10
2x + 20 = 2x + 20 + 10
2x - 2x = 30 - 20
x = 10
Therefore, We got the value of, x = 10.
Hence,
The present age of John's, x = 10 years
Then, the present age of John's father, 2x + 10 = 2 × 10 + 10 = 20 + 10 = 30 years
Answered by
40
The present age of John's father is 10 years more than twice the present age of John. After 10 years, age of John's father will be twice the John's age. Find their current ages...
_________________
✒Given : -
- The present age of John's father is 10 years more than twice the present age of John...
- After 10 years, age of John's father will be twice the John's age...
✒To Find : -
- Current ages = ?
✒Let ,
- Present age of John's be = y
- Then, Present age of his father will be = 2y + 10
✒After 10 years : -
- John's age = y + 10
- His father's age = 2y + 10 + 10
✒Now ,
✒On Substituting Values : -
✒Therefore , Value of y is 10 ..
✒So ,
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