Math, asked by anandarnav21122006, 10 months ago

The present age of John's father is 10 years more than twice the present age of John. After 10 years, age of John's father will be twice the John's age. Find their current ages.

Answers

Answered by jtg07
21

Step-by-step explanation:

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===>

The present age of John's father is 10 years more than twice the present age of John. After 10 years, age of John's father will be twice the John's age. Find their current ages.

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===> let the present age of John be 'x'

===> the present age of his father will be 10+2x

after 10 years,

===> age of John will be 10+x

===> age of his father will be 10+2x+10

using condition,

===> 20+2x = 2(10+x)

solve further you will get the answer

Answered by pulakmath007
1

Answer:

Let the present ages of father and son be 2x + 10 and x years respectively.

By the given condition

(2x+10+10) = 2(x+10)

2x+20=2x+40

Which is unsolvable

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