Question

the present age of man is 3 times that his son. ten years ago, he was 5 times as old as his son, then age of son 3 years later ( in years) is​

Answer 1

Answer:

x equals to 20

Step-by-step explanation:

Let's the man age to be x.

Ten years ago he was 5 times the age of his son.

Therefore , 3x-10 equals to 5 (x equals to -10)

3x-10 equals to 5x-50

2x equals to 40

Thus 40/2 equals to 20

If the answer is correct pls make me the brainlest

Answer 2

Step-by-step explanation:

$\bf\underline{\underline{\red{Given:-}}}$

• The present age of a man is 3 times that of his son.

• Ten years ago he was 5 times as old as his son.

$\bf\underline{\underline{\blue{To\:Find:-}}}$

• The age of his son 3 years later.

$\bf\underline{\underline{\green{Solution:-}}}$

$\underline{\pink{\bf Case\: 1:-}}$

The present age of a man is 3 times that of his son.

Let the present age of son be x

Present age of the man = 3x

$\underline{\orange{\bf Case\: 2:-}}$

Ten years ago:-

Age of son

= Present age of son - 10

= x - 10

Age of man

= Present age of man - 10

= 3x - 10

We have,

Age of son 10 years ago = x - 10

Age of man 10 years ago = 3x - 10

Given, Ten years ago the man was 5 times as old as his son.

So:-

$\rm \implies 3x - 10 = 5(x - 10)$

$\rm \implies 3x - 10 = 5x - 50$

$\rm \implies 3x - 5x = -50 + 10$

$\rm \implies -2x = -40$

$\rm \implies x = \dfrac{ - 40}{ - 2}$

$\rm \implies x = 20$

Present age of son = x = 20

We need to find the age of son 3 years later.

Age of son 3 years later

= Present age of son + 3

= x + 3

= 20 + 3

= 23

$\underline{ \boxed{\rm \purple{\therefore Age \: of \: son \: 3 \: years \: later \: = 23 \: years}}}$