The present age of man is 3 years more than three times the age of his sin Three years hence the mans age willl be 10 years more than twice the age of his son determine therir present ages
Answers
Let the present age of the son of that man be x years
So, age of man will be 3 times of x + 3 years
⇒ ( 3x + 3 ) years
Given, 3 years hence man's age will be 10 years more than twice the age of his son
Age of man 3 years hence = Present age + 3 years
= ( 3x + 3 )years + 3 years
= ( 3x + 6 ) years ------ : ( 1 )
Age of son = Present age + 3 years
= x years + 3 years
= ( x + 3 ) years ------: ( 2 )
According to the questions : -
Three years hence the mans age will be 10 years more than twice the age of his son
Man's age 3 years hence = 10 years more than the twice of his son's age
From ( 1 ) & ( 2 )
⇒ ( 3x + 6 ) years = 2( x + 3 ) years + 10 years
⇒ ( 3x + 6 ) = 2( x ) + 2( 3 ) + 10
⇒ 3x + 6 = 2x + 6 + 10
⇒ 3x - 2x = 10 + 6 -6
⇒ x = 10
∴ Present age of man's son = x years = 10 years
∴ Present age of man = 3x + 3 = 3( 10 ) + 3 years
Present age of man = 33 years
Let the present age of the son = 'x'.
Given that the man is 3 years more than three times the age of his son.
So, the present age of the man = 3x + 3.
Three years hence:
⇒ Age of son = x + 3.
⇒ Age of man = 3x + 6.
Given that the mans age will be 10 years more than twice the age of his son.
⇒ 3x + 6 = 2(x + 3) + 10
⇒ 3x + 6 = 2x + 6 + 10
⇒ 3x - 2x = 16 - 6
⇒ x = 10.
Then,
⇒ 3x + 3
⇒ 3(10) + 3
⇒ 33.
Therefore,
⇒ The present age of son = 10 years.
⇒ The present age of man = 33 years.
Hope this helps!