Question

The present age of Meena’s mother is 5 times that of Meena’s age. The sum of their ages 5 years ago was 32. What are their present ages ?​

Answer 1

Let x be the age of meena

then her mother's age will be 5x

5 years ago:

meenas age=(x-5)

her mother's age = (5x-x)

sum of their ages =(x-5) +(5x-5) =32

5x-5+x-5=32

5x-5-5+x=32

5x-10+x=32

6x-10=32

6x=32+10

6x=40

x=40/6

x=7

therefore meenas age is 7

since her mother's age is 5x

5×7=35

therefore her mother's age is 35

Answer 2

Given :

• The present age of Meena’s mother is 5 times that of Meena’s age.
• The sum of their ages 5 years ago was 32 .

To Find :

• Present Age of Meena and her mother .

Solution :

$\longmapsto\tt{Let\:the\:age\:of\:Meen\:be=x}$

As Given that The present age of Meena’s mother is 5 times that of Meena’s age. So ,

$\longmapsto\tt{Mother=5x}$

Before 5 years :

$\longmapsto\tt{Age\:of\:Meena=x-5}$

$\longmapsto\tt{Age\:of\:Mother=5x-5}$

A.T.Q :

$\longmapsto\tt{x-5+5x-5=32}$

$\longmapsto\tt{6x-10=32}$

$\longmapsto\tt{6x=32+10}$

$\longmapsto\tt{6x=42}$

$\longmapsto\tt{x=\cancel\dfrac{42}{6}}$

$\longmapsto\tt\bf{x=7}$

Value of x is 7 .

Therefore :

$\longmapsto\tt{Present\:Age\:of\:Meena=x}$

$\longmapsto\tt\bf{7\:yrs}$

$\longmapsto\tt{Present\:Age\:of\:Mother=5(7)}$

$\longmapsto\tt\bf{35\:yrs}$