Question

The present age of Mohan is three times the age of son. After 8

years, the sum of their ages is 72 years. Find their present ages​

Answer 1

Answer:

x=14

Step-by-step explanation:

at present

mohans age-3x

sons age-x

after 8 years

mohans age 3x+8

sons age x+8

3x+8+x+8=72

4x+16=72

4x=72-16

4x=56

x=56÷4

x=14

Answer 2

Direct answer:

Present age of Mohan is 42 years and his son's age is 14 years.

Given:

★ The present age of Mohan is three times the age of his son.

★ After 8 years, the sum of their ages is 72.

To Find:

The present ages of Mohan and his son.

Solution:

In order to find the current ages of Mohan and his son, we must form algebraic expressions with the given data, analyze them and manipulate the data. This will give provide us the required answers.

Let us assume that the age of Mohan's son is x. This means that the age of Mohan who is aged three times more than his son is 3x.

➡ Present age of son = x

➡ Present age of Mohan = 3x

Then, it is mentioned that after 8 years the sum of their ages is 72. This means that we have to add 8 to the current ages of both Mohan and his son.

➡ Age of son after 8 years = x + 8

➡ Age of Mohan after 8 years = 3x + 8

✳ Forming an algebraic expression from the given data:

$\sf{\implies\:x+8+3x+8=72}$

✳ Grouping and adding the variables and constants:

$\sf{\longrightarrow\:x+3x+8+8=72}$

$\sf{\longrightarrow\:4x+16=72}$

✳ Transposing the constants to the RHS:

$\sf{\longrightarrow\:4x=72-16}$

$\sf{\longrightarrow\:4x=56}$

$\sf{\longrightarrow\:x=\dfrac{56}{4}}$

$\sf{\longrightarrow\:x=14}$

Substituting the values of x,

Present age of son = x = 14 years

Present age of Mohan = 3x = 42 years