Math, asked by viktimalvi, 6 hours ago

The present age of mother and her daughter is .x years and y years respectively. The difference of their reciprocal is ? ​

Answers

Answered by devindersaroha43
1

Answer:

Step-by-step explanation:

Let x and y be the present age of mother and her daughter.

Therefore,

x+y=50

⇒x=50−y (1)

After 20 years, mother's age will be twice her daughter's age at the time.

x+20=2(y+20)

⇒x−2y=20(2)

From equation (1)&(2), we have

50−y−2y=20

3y=30

⇒y=10

Substituting the value of y in equation (1), we get

x=50−10=40

Hence the present age of mother and her daughter is 40 and 10 years respectively.

Answered by nishalakum79
1

Answer:

1/x>1/y

x is mother's age

y is daughter's age

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