The present age of mother and her daughter is .x years and y years respectively. The difference of their reciprocal is ?
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Answered by
1
Answer:
Step-by-step explanation:
Let x and y be the present age of mother and her daughter.
Therefore,
x+y=50
⇒x=50−y (1)
After 20 years, mother's age will be twice her daughter's age at the time.
x+20=2(y+20)
⇒x−2y=20(2)
From equation (1)&(2), we have
50−y−2y=20
3y=30
⇒y=10
Substituting the value of y in equation (1), we get
x=50−10=40
Hence the present age of mother and her daughter is 40 and 10 years respectively.
Answered by
1
Answer:
1/x>1/y
x is mother's age
y is daughter's age
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