Question

The present age of mother is six times the age of her daughter. After 20 years, age of mother will become two times the age of her daughter. Find their present ages.

Answer 1

Answer:

mother age 30

daughter age 5

Step-by-step explanation:

let the daughter's age be y

let mother's age be x

now,

x=6y

x-6y=0 (a)

After 20 years, x+20 ;y +20

x+20=2(y+20)

x+20=2y+40

x -2y=40-20

x-2y=20 (b)

By elimination method for(a) & (b)

y = 5 & x=30

Alternative method:

let the daughter's age be x

mother's age : 6x

After 20 years , daughter age is

x + 20 ; Mother's age is 6x + 20

now given, mother's age is two times age of daughter : 6x+20=2(x+20)

6x+20=2x+40

6x-2x=40-20

4x=20

x=20/4

x=5

daughter's age = 5

mother's age =5*6=30