Question

the present age of Mr.Ashok is equal to the square of his son's present age.One year ago Mr.Ashok was eight times as old as his son.Find their presunt age by quadratic equation

Answer 1

Heya

Let the present age of Mr.Ashok be x

And his son's age be y

According to the question,

x= y²...(1)

x-1= 8(y-1)

x-1 = 8y-8

x-8y-1+8=0

x-8y+7=0...(2)

Substituting eq 1 in 2

y²-8y+7 = 0

y²-7y-y+7= 0

y(y-7) -1(y-7)=0

(y-1)(y-7)=0

y= 1 or 7

When y=1, x=1(this can't be possible)

When y=7

Mr.Ashok's age = 7²=49yrs and his son's age is 7yrs.

Hope it helps^_^

Answer 2

Answer:

Sons age is 7 and Ashok age is $7^{2}$ = 49

Step-by-step explanation:

Let the age of Ashok = a

Let the age of his son = b

Its given that

a = $b^{2}$

One year ago

(a-1) = 8(b-1)

($b^{2}$ - 1) = 8(b-1)

($b^{2}$ - 1) = 8b - 8

$b^{2}$ - 8b - 7 = 0

$b^{2}$ - 7b - b - 7 = 0

b(b-7) - 1(b-7) = 0

(b-1)(b-7) = 0

b = 1 or b = 7

Here we will consider b = 7

So sons age is 7 and Ashok age is $7^{2}$ = 49