Math, asked by kumarmrigank009, 9 months ago

the present age of Radhika is mother is 6 time Radhika is age
5 year hence her age will be 20year more than that of radhika age . find the present age.​

Answers

Answered by αmαn4чσu
53

 \large{\textbf{\underline{$Radhika \:present \:age = 4 years$}}}

 \large{\textbf{\underline{$Mother\: present \:age = 24 years$}}}

 \huge{\textbf{\underline{As per Question:-}}}

Let the present age of Radhika and his mother be x and y years.

 \huge{\textbf{\underline{Solution:-}}}

  • Radhika mother is six times Radhika age.

 y = 6x

★ 5 years hence.

Age of her mother will be =

( y + 5)years.

Age of Radhika will be =

( x + 5) years.

  • 5 years hence mother age will be 20 years more than radhika age.

 ( y + 5) = ( x + 5) + 20

 y + 5 = x + 25

  • put the value of y.

 6x + 5 = x + 25

 6x-x = 25 -5

 5x = 20

 x = \dfrac{20}{5}

 \therefore \textbf{$x = 4 years$}

Mother age is :-

y = 6x

y = 6 × 4

\therefore y = 24 years

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